Written on by Temani Afif
You must have seen those sliders of images that have an infinite loop animation. They are also called infinite carousels where all the images appear and disappear indefinitely. To create such sliders, most of the tricks rely on JavaScript or on duplicating the images. In this post, we will see how to do this without JavaScript and without duplicating any of the images.
We are going to use a few CSS tricks to build something like the below:
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The HTML code is as simple as a list of images within a container:
<div class="gallery">
<img src="" alt="">
<img src="" alt="">
<img src="" alt="">
<img src="" alt="">
</div>
As I said in the introduction, we are not going to duplicate any of the images so all of them are unique. We also don’t need any complex code structure like a lot of divs.
We are going to rely on CSS Grid for the image placement.
.gallery {
display: grid;
overflow: hidden;
}
.gallery > img {
grid-area: 1/1;
height: 200px;
aspect-ratio: 1.5;
object-fit: cover;
}
Nothing complex so far. We create a grid with specific dimensions (it’s up to you to adjust it as you want) then we place all the images above each other inside the same grid track using grid-area: 1/1.
Let’s now tackle the important part of our code: The animation. The trickiest part here is to simulate the infinite loop without duplicating the image. We need to also consider the number of images.
In our case, we are using four images and we are going to split our animation into two steps. The first step is illustrated below:
The red dashes are the limit of our container. All the images need to move to the left by three times their size which will make the last image visible. This first step can be done by using transform: translate(-300%).
The next step is to move the first image right before the last one then translate it again until it becomes the visible image.
Our keyframes will look like below:
@keyframes r {
/* Step 1 */
0% {transform: translate(0)}
X% {transform: translate(-300%)}
/* Step 2 */
(X + .01)% {transform: translate( 100%)}
100% {transform: translate(0)}
}
We first move our image to the left by -300%. Then we put it back to the right using 100%. Note that this should happen instantly that is why I am using X + .01. I am adding a tiny percentage to the previous state. Finally, we get back to the initial state.
Now we need to find the value of X. In the first step, the image is moving by three times its size (from 0% to -300%) while in the second step it’s moving by one time its size (from 100% to 0%). This means that the first step needs to stay three times longer than the second one. We have the following formulas:
T1 + T2 = 100%
T1 = 3*T2
Which give us
T1 = (4/3)*100% = 75%
The first step, need to run 75% of the keyframes so X needs to be equal to 75%. We can also omit the 0% and 100% from the keyframes since they are the default values and use only the following code:
@keyframes r {
75% {transform: translate(-300%)}
75.01% {transform: translate( 100%)}
}Oops, the animation seems to be broken and only one image is visible. Don’t worry, I didn’t make any mistakes and what you see is logical. Remember that in the Grid configuration we placed all the images above each other inside the same grid track. This means that all of them are moving together and only the top image is visible.
To fix this, we need to consider animation delays. The logic is as follows: We have fours images and the duration is defined by the variable --d so we will use var(--d)/4 and we define the delays like below:
The 1st image: calc(0*var(--d)/4)
The 2nd image: calc(1*var(--d)/4)
The 3rd image: calc(2*var(--d)/4)
The 4th image: calc(3*var(--d)/4)
Almost good but we have to wait for the animation to run. This is because we are using positive delays making the last image (the one at the top) start late. To fix this we simply make the delay negative and we are good:
The full code again:
.gallery {
--d: 6s; /* duration */
display: grid;
overflow: hidden;
-webkit-mask: linear-gradient(90deg,#0000,#000 10% 90%,#0000);
}
.gallery > img {
grid-area: 1/1;
height: 200px;
aspect-ratio: 1.5;
object-fit: cover;
animation: r var(--d) linear infinite;
}
.gallery > img:nth-child(2) {animation-delay: calc(1*var(--d)/-4)}
.gallery > img:nth-child(3) {animation-delay: calc(2*var(--d)/-4)}
.gallery > img:nth-child(4) {animation-delay: calc(3*var(--d)/-4)}
@keyframes r {
75% {transform: translate(-300%)}
75.01% {transform: translate( 100%)}
}
With only a few lines of code, we get an infinite slider that works without duplicating the images.
We can still do better and introduce another variable to make the code generic so it can work with any number of images.
For this we will rely on Sass:
$n:5; /* number of images*/
.gallery {
--d: 10s; /* duration */
display: grid;
overflow: hidden;
width: 380px;
-webkit-mask: linear-gradient(90deg,#0000,#000 10% 90%,#0000);
}
.gallery > img {
grid-area: 1/1;
width: 100%;
aspect-ratio: 1.5;
object-fit: cover;
animation: r var(--d) linear infinite;
}
@for $i from 2 to ($n + 1) {
.gallery > img:nth-child(#{$i}) {animation-delay: calc(#{(1 - $i)/$n}*var(--d))}
}
@keyframes r {
#{100*($n - 1)/$n}% {transform: translate((1 - $n)*100%)}
#{100*($n - 1)/$n + .01}% {transform: translate(100%)}
}
When we used 4 images we had to translate by -300% so with N images we need (1 - N)*100%. For the delays, we use a loop to set the value for all the images.
For the keyframes, remember the formulas we used:
T1 + T2 = 100%
T1 = 3*T2
Instead of 3, we will use N - 1 to get
T1 + T2 = 100%
T1 = (N - 1)*T2
Which will give us
T1 = 100% * N/(N - 1)
That’s it! With simple math, we transformed our code into a generic one that can work with any number of images:
Without JavaScript and without duplicating any of the images, we made an infinite image slider with an optimized code. Not to mention efficiency since we are animating only the transform property. To this, we added a touch of Sass to be able to easily control the number of images.
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